1-x^2=2(x^2-5)

Solution for 1-x^2=2(x^2-5) equation:

Simplifying
1 + -1x2 = 2(x2 + -5)

Reorder the terms:
1 + -1x2 = 2(-5 + x2)
1 + -1x2 = (-5 * 2 + x2 * 2)
1 + -1x2 = (-10 + 2x2)

Solving
1 + -1x2 = -10 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
1 + -1x2 + -2x2 = -10 + 2x2 + -2x2

Combine like terms: -1x2 + -2x2 = -3x2
1 + -3x2 = -10 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
1 + -3x2 = -10 + 0
1 + -3x2 = -10

Add '-1' to each side of the equation.
1 + -1 + -3x2 = -10 + -1

Combine like terms: 1 + -1 = 0
0 + -3x2 = -10 + -1
-3x2 = -10 + -1

Combine like terms: -10 + -1 = -11
-3x2 = -11

Divide each side by '-3'.
x2 = 3.666666667

Simplifying
x2 = 3.666666667

Take the square root of each side:
x = {-1.914854216, 1.914854216}